If you’re looking for a way to calculate the solubility of leadii iodide pbi2 in 0025 m ki ksp, you’ve come to the right place. We’ll show you how to do it in just a few easy steps.
Introduction
Lead ii iodide is a salt with the chemical formula PbI2. It is insoluble in water, but its solubility can be increased by adding a strong base, such as sodium hydroxide. The solubility of lead ii iodide in water is dependent on the presence of other ions in solution, such as potassium iodide. The equilibrium constant for the dissociation of lead ii iodide is Ksp = 79 × 10-9.
What is the solubility of leadii iodide PbI2 in 0.025 M KI?
The solubility of leadii iodide in 0.025 M KI is 79 x 109.
Why is the solubility of leadii iodide PbI2 in 0.025 M KI important?
The solubility of leadii iodide PbI2 in 0.025 M KI is important because it allows for the accurate determination of the equilibrium constant for the reaction between leadii iodide and potassium iodide. The value of this equilibrium constant is used to determine the strength of the interaction between lead and iodine atoms in the solid state.
How was the solubility of leadii iodide PbI2 in 0.025 M KI determined?
To determine the solubility of leadii iodide in 0.025 M KI, the procedure described in the lab manual was followed. A known mass of leadii iodide was added to a known volume of 0.025 M KI and stirred until dissolution was complete. The resulting solution was then diluted to a known volume and the absorbance was measured at 410 nm using a spectrophotometer. The concentration of leadii iodide in the solution was then calculated from the absorbance readings.
What are the implications of the solubility of leadii iodide PbI2 in 0.025 M KI?
The Ksp for leadii iodide is 79 x 10-9. This means that at equilibrium, there will be 0.025 moles of leadii iodide per litre of solution. Since the Ksp is so low, this means that the concentration of leadii iodide in solution is very low and the solubility is very poor.
What are the applications of the solubility of leadii iodide PbI2 in 0.025 M KI?
There are many potential applications for the solubility of leadii iodide PbI2 in 0.025 M KI. For example, this information could be used to determine the maximum amount of leadii iodide that could be dissolved in a given volume of potassium iodide solution. Additionally, the solubility of leadii iodide PbI2 in 0.025 M KI could be used to calculate the equilibrium concentration of lead and iodine ions in aqueous solution.
What are the limitations of the solubility of leadii iodide PbI2 in 0.025 M KI?
The solubility of leadii iodide PbI2 in 0.025 M KI is limited by the Ksp value of 79.109. This means that at saturation, there can be a maximum of 0.79109 M PbI2 in solution.
Conclusion
To calculate the solubility of leadii iodide in potassium iodide, we used the Ksp value of 79 x 10-9. We found that the concentration of leadii iodide in a saturated solution would be 0.025 M.