Introduction

When trying to initialize a constant variable with a non-constant value, you may see the error message “error initializer element is not constant”. This error means that the compiler is unable to evaluate the initializer expression at compile time, so it cannot create a constant variable.

There are several reasons why this error might occur. For example, if you are trying to initialize a constant with the result of a function call, the function must be marked as constexpr in order for the compiler to evaluate it at compile time. Additionally, all of the values used in the initializer expression must be known at compile time in order for the compiler to create a constant variable.

If you see this error, it is likely that you will need to find another way to initialize your constant variable. One option is to use a constexpr function to calculate the value of the variable at compile time. Alternatively, you can initialize your constant variable with a literal value instead of an expression.

What is an error initializer element?

An error initializer element is a piece of code that is not initialized properly, and thus causes an error when trying to compile the code.

Causes of error initializer element

The “error initializer element is not constant” message is caused by trying to initialize a static or instance variable with a non-constant value.

This error message can also be caused by trying to use a non-static field in a static context. In this case, you need to make the field static as well.

How to fix error initializer element

If you receive the error message “initializer element is not constant,” it means that you are trying to initialize a static variable with a value that is not a compile-time constant. A compile-time constant is a value that can be evaluated by the compiler and is therefore known at compile time. In order to fix this error, you need to make sure that the value you are trying to initialize your static variable with is a compile-time constant.

One way to do this is to use the const keyword. The const keyword tells the compiler that the value of the variable is not going to change and it can be evaluated at compile time. By using const, you can make sure that your static variable is initialized with a compile-time constant.

another way to fix this error is to initialize your static variable with a literal value. A literal value is a value that is hard-coded into your program and is known at compile time. For example, if you want to initialize a static variable with the number 42, you can do so by writing:

static int myVariable = 42;

since 42 is a literal value, it can be evaluated by the compiler and used to initialize your static variable.

Conclusion

In general, you can’t use something that isn’t constant as part of a declaration of something that is constant. The error message is telling you that you’ve declared something to be constant (either directly, or by using the keyword “static”), but you’ve included a part that can’t be constant.